提交时间:2024-01-07 15:38:23

运行 ID: 230079

#include <bits/stdc++.h> using namespace std; int n,a[100005],x,y,ans1,ans2; int main() { cin >> n; for (int i=1;i<=n;i++) { cin >> a[i]; } cin >> x >> y; for (int i=x;i<y;i++) { ans1+=a[i]; } for (int i=x;i!=y;i--) { if (i==1) { ans2+=a[n]; i=n+1; }else { ans2+=a[i-1]; } } //cout << ans1 << ' ' << ans2 << endl; cout << min(ans1,ans2); return 0; }